SOLUTION: Identify the maximum or minimum (vertex), zeros, and axis of symmetry line and show the graph. y=x^2+2x+1

Hi

Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin

Using the vertex form of a parabola,  where(h,k) is the vertex

 y = x^2+2x+1           |Completing the square

 y = (x+1)^2       |Vertex is Pt(-1,0)& a Minimum as Parbola opens upward (a> 0)    x = -1, the line of symmetry

 0 = (x+1)^2       x = -1