SOLUTION: Identify the vertex of the parabola y=4x^2+8x+6

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Question 3945: Identify the vertex of the parabola
y=4x^2+8x+6
Answer by stop12345now(6) About Me  (Show Source):
You can put this solution on YOUR website!
x coordinate of vertex is -(b/2a)= -(8/(4*2))=-8/8=-1
y coor- plug in x coor. into equation for x.
4(-1)^2+8(-1)+6
= 4-8+6
= 2
vertex is at (-1,2)