SOLUTION: This problem is in my college algebra for calculus class under quadratic equations. The book gives the answer but not how it is worked out. Can you please help. It says to solve 3y

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: This problem is in my college algebra for calculus class under quadratic equations. The book gives the answer but not how it is worked out. Can you please help. It says to solve 3y      Log On


   

Question 363607: This problem is in my college algebra for calculus class under quadratic equations. The book gives the answer but not how it is worked out. Can you please help. It says to solve 3y^3-5y^2-2y=0
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
3y^3-5y^2-2y=0
y(3y^2-5y-2)=0
y(3y^2-6y+y-2)=0 Factoring by grouping.
y(3y(y-2)+(y-2))=0
y(3y+1)(y-2)=0
y=0, y=-1/3, y=2
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Ed