SOLUTION: A ball is thrown into the air with the velocity of 48 feet per second. With h for height and t for time and height determined with h=16tsquared+48t=4. How may seconds will the

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: A ball is thrown into the air with the velocity of 48 feet per second. With h for height and t for time and height determined with h=16tsquared+48t=4. How may seconds will the       Log On


   

Question 35679: A ball is thrown into the air with the velocity of 48 feet per second.
With h for height and t for time and height determined with h=16tsquared+48t=4.
How may seconds will the ball reach maximum height.
What is the maximum height.
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Did you state this problem correctly? You have two equal signs in the formula for h. Please take another look at this.

R^2 at SCC