SOLUTION: solve by using the quadratic formula 9x^2-270=0

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Question 35551This question is from textbook algebra 1 prentice hall
: solve by using the quadratic formula
9x^2-270=0
This question is from textbook algebra 1 prentice hall

Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
+9x%5E2-270=0+
a = 9
b = 0
c = -270
x+=+%28-0+%2B-+sqrt%28+0%5E2-4%2A9%2A%28-270%29+%29%29%2F%282%2A9%29+
Working left to right inside the root
x+=+%28+0+%2B-+sqrt%28+-4%2A9%2A%28-270%29+%29%29%2F%282%2A9%29+
x+=+%28+0+%2B-+sqrt%28+-36%2A%28-270%29+%29%29%2F%282%2A9%29+
x+=+%28+0+%2B-+sqrt%28+-36%2A%28-270%29+%29%29%2F%282%2A9%29+
x+=+%28+0+%2B-+sqrt%28+9720%29+%29%2F%282%2A9%29+
and the denominator
x+=+%28+0+%2B-+sqrt%28+9720%29+%29%2F%2818%29+
Now the root itself
x+=+%28+0+%2B-+18+%28sqrt%2830%29%29+%29%2F%2818%29+
Reduce the fraction
+x+=+%28sqrt%2830%29%29+ and +x+=+-+%28sqrt+%2830%29%29+