SOLUTION: y=x^2-x-23 find the vertex

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Question 355148: y=x^2-x-23 find the vertex
Found 2 solutions by nyc_function, checkley77:
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
y = x^2-x-23 find the vertex


The vertex is a point in the form (x,y).


We first find x.


x = -b/2a


x = -(-1)/2(1)


x = 1/2


To find y, replace every x in the given function with 1/2 and do the math.


y = (1/2)^2-(1/2)- 23


y = 1 - 1/2 - 23


y = -45/2


The vertex is (1/2, -45/2).




Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2-x-23
Solving the equation for x we get x=(5.32 & -4.32).
The nid point is 5.43-4.32=1/2=.5
y=.5^2-.5-23
y=.25-.5-23
y=.25-23.5
y=-23.25
The VERTEX(.5,-23.25)
+graph%28+300%2C+200%2C+-6%2C+6%2C+-25%2C+10%2C+x%5E2+-x+-23%29+ (graph 300x200 pixels, x from -6 to 6, y from -25 to 10, x^2 -x -23).