SOLUTION: what are the solutions of the equation x^2-12x+32=0
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Question 351063
:
what are the solutions of the equation x^2-12x+32=0
Answer by
nerdybill(7384)
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x^2-12x+32=0
Factoring the left side:
(x-4)(x-8)=0
Setting each term in parentheses to zero we get:
x = {4, 8}