SOLUTION: State the value of the discriminant: 10x^2+5x-5=0

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Question 318628: State the value of the discriminant: 10x^2+5x-5=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

From 10x%5E2%2B5x-5 we can see that a=10, b=5, and c=-5


D=b%5E2-4ac Start with the discriminant formula.


D=%285%29%5E2-4%2810%29%28-5%29 Plug in a=10, b=5, and c=-5


D=25-4%2810%29%28-5%29 Square 5 to get 25


D=25--200 Multiply 4%2810%29%28-5%29 to get %2840%29%28-5%29=-200


D=25%2B200 Rewrite D=25--200 as D=25%2B200


D=225 Add 25 to 200 to get 225


So the discriminant is D=225


Since the discriminant is greater than zero, this means that there are two real solutions.