SOLUTION: Find the product of the solutions of this equation 15x^2+23x-41=0

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Question 308327: Find the product of the solutions of this equation 15x^2+23x-41=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
15x%5E2%2B23x-41=0
x+=+%28-23+%2B-+sqrt%28+23%5E2-4%2A15%2A%28-41%29+%29%29%2F%282%2A15%29+
x+=+%28-23+%2B-+sqrt%28+529%2B2460+%29%29%2F%2830%29+
x+=+%28-23+%2B-+sqrt%28+2989%29%29%2F%2830%29+
x+=+%28-23+%2B-+sqrt%28+49%2A61%29%29%2F%2830%29+
x+=+%28-23+%2B-+7sqrt%28+61%29%29%2F%2830%29+
30x=-23%2B-7sqrt%2861%29%29
30x1%2A30x2=%28-23%2B7sqrt%2861%29%29%28-23-7sqrt%2861%29%29
900%2Ax1%2Ax2=529-49%2861%29
900%2Ax1%2Ax2=-2460
x1%2Ax2=-2460%2F900
x1%2Ax2=-41%2F15
Look at the original equation and compare.