SOLUTION: Please help me solve this problem 2x^-8x+3=0 I remember I have to divide both sides by 2 . Then use distribution. I appreciate your time.

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Question 303743: Please help me solve this problem 2x^-8x+3=0
I remember I have to divide both sides by 2 . Then use distribution. I appreciate your time.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic


ax%5E2%2Bbx%2Bc=0


the general solution using the quadratic equation is:


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29




So lets solve 2%2Ax%5E2-8%2Ax%2B3=0 ( notice a=2, b=-8, and c=3)





x+=+%28--8+%2B-+sqrt%28+%28-8%29%5E2-4%2A2%2A3+%29%29%2F%282%2A2%29 Plug in a=2, b=-8, and c=3




x+=+%288+%2B-+sqrt%28+%28-8%29%5E2-4%2A2%2A3+%29%29%2F%282%2A2%29 Negate -8 to get 8




x+=+%288+%2B-+sqrt%28+64-4%2A2%2A3+%29%29%2F%282%2A2%29 Square -8 to get 64 (note: remember when you square -8, you must square the negative as well. This is because %28-8%29%5E2=-8%2A-8=64.)




x+=+%288+%2B-+sqrt%28+64%2B-24+%29%29%2F%282%2A2%29 Multiply -4%2A3%2A2 to get -24




x+=+%288+%2B-+sqrt%28+40+%29%29%2F%282%2A2%29 Combine like terms in the radicand (everything under the square root)




x+=+%288+%2B-+2%2Asqrt%2810%29%29%2F%282%2A2%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




x+=+%288+%2B-+2%2Asqrt%2810%29%29%2F4 Multiply 2 and 2 to get 4


So now the expression breaks down into two parts


x+=+%288+%2B+2%2Asqrt%2810%29%29%2F4 or x+=+%288+-+2%2Asqrt%2810%29%29%2F4



Now break up the fraction



x=%2B8%2F4%2B2%2Asqrt%2810%29%2F4 or x=%2B8%2F4-2%2Asqrt%2810%29%2F4



Simplify



x=2%2Bsqrt%2810%29%2F2 or x=2-sqrt%2810%29%2F2



So the solutions are:

x=2%2Bsqrt%2810%29%2F2 or x=2-sqrt%2810%29%2F2