SOLUTION: SQRT(x)-2x-13=0 move the constant term to the right side of the equation.

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Question 302408: SQRT(x)-2x-13=0 move the constant term to the right side of the equation.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I don't know what all those instructions are about, but if you want to solve for x:
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SQRT(x)-2x-13=0
sqrt%28x%29+=+2x+%2B+13
Square both sides
x+=+4x%5E2+%2B+52x+%2B+169
4x%5E2+%2B+51x+%2B+169+=+0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 4x%5E2%2B51x%2B169+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%2851%29%5E2-4%2A4%2A169=-103.

The discriminant -103 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -103 is + or - sqrt%28+103%29+=+10.1488915650922.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+4%2Ax%5E2%2B51%2Ax%2B169+%29

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No real solutions.