SOLUTION: I need help solving {{{2x^2+2=-3x}}}by completing the perfect square to get exact solutions. Based on the solutions I then need to describe the position of the graph of F(x)={{{2x

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: I need help solving {{{2x^2+2=-3x}}}by completing the perfect square to get exact solutions. Based on the solutions I then need to describe the position of the graph of F(x)={{{2x      Log On


   



Question 29638: I need help solving 2x%5E2%2B2=-3xby completing the perfect square to get exact solutions. Based on the solutions I then need to describe the position of the graph of F(x)=2x%5E2%2B3x%2B2on the x-y plane.
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
+2x%5E2%2B2+=+-3x+
+2x%5E2%2B3x+=+-2+

Now complete this square on the LHS:
+x%5E2%2B%283%2F2%29x+=+-1+

2a = 3/2
--> a = 3/4
--> a%5E2+=+9%2F16

+x%5E2%2B%283%2F2%29x+%2B+9%2F16+=+-1+%2B+9%2F16

--> +%28x+%2B+%283%2F4%29%29%5E2+=+-7%2F16+

So, +x+%2B+%283%2F4%29+=+sqrt%28-7%2F16%29+ or +x+%2B+%283%2F4%29+=+-+sqrt%28-7%2F16%29+
+x+=+-+%283%2F4%29+%2B+sqrt%28-7%2F16%29+ or +x+=+-+%283%2F4%29+-+sqrt%28-7%2F16%29+
+x+=+-+%283%2F4%29+%2B+%281%2F4%29sqrt%28-7%29+ or +x+=+-+%283%2F4%29+-+%281%2F4%29sqrt%28-7%29+
+x+=+%28-3+%2B+sqrt%28-7%29%29%2F4+ or +x+=+%28-3+-+sqrt%28-7%29%29%2F4+

Well, you have a square root of a negative number, so this is nothing "real". In essence, there are no solutions... the quadratic does not cross the x-axis and will lie above it. As to where it lies, well the work done to get the equation in the form +%28x+%2B+%283%2F4%29%29%5E2+%2B+7%2F16+=+0 tells us that the vertex lies at x=(-3/4).

Now, for the original equation, +y=2x%5E2%2B3x%2B2+, when we put this value of x in, we get y=7/8... the 7/16 in the "completed the square" version of the equation is a scaled version...because we divided everything by 2, if you remember.

If we plot the original curve, this is confirmed:
+graph%28300%2C300%2C-3%2C4%2C-2%2C2%2C2x%5E2%2B3x%2B2%29+

jon.