Question 294549: x^2+4x+4=7
Answer by helpnalgebra(91)   (Show Source):
You can put this solution on YOUR website! x^(2)+4x+4=7
x^(2)+4x-3=0
x=(-b\~(b^(2)-4ac))/(2a) where ax^(2)+bx+c=0
x=(-4\~((4)^(2)-4(1)(-3)))/(2(1))
x=(-4\2~(7))/(2(1))
x=(-4\2~(7))/(2)
x=(-4+2~(7))/(2)
x=-2+~(7)
x=(-4-2~(7))/(2)
x=-2-~(7)
The final answer is the combination of both solutions.
x=-2+~(7),-2-~(7)_xAPPR0.65,-4.65
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