Question 294547: x^2-4x-7=0
Answer by helpnalgebra(91)   (Show Source):
You can put this solution on YOUR website! x^(2)-4x-7=0
x=(-b\~(b^(2)-4ac))/(2a)
x=(-(-4)\~((-4)^(2)-4(1)(-7)))/(2(1))
x=(4\~((-4)^(2)-4(1)(-7)))/(2(1))
x=(4\2~(11))/(2(1))
x=(4\2~(11))/(2)
x=(4+2~(11))/(2)
x=2+~(11)
x=(4-2~(11))/(2)
x=2-~(11)
The final answer is the combination of both solutions.
x=2+~(11),2-~(11)_xAPPR5.32,-1.32
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