Question 290877: find an equation for the parabola with vertex (-2,5) and y-intercept 1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find an equation for the parabola with vertex (-2,5) and y-intercept 1
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Form: y = a(x-h)^2 + k
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h = -2, k = 5
Goes thru (0,1)
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Using the vertex
y = a(x+2)^2 + 5
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Using the intercept:
1 = a(0+2)^2 + 5
1 = 4a + 5
4a = -4
a = -1
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Equation:
y = -(x+2)^2 + 5
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Cheers,
Stan H.
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