SOLUTION: Find the vertex of the parabola: y=-x²+1/2x+2

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Find the vertex of the parabola: y=-x²+1/2x+2      Log On


   

Question 290628: Find the vertex of the parabola:
y=-x²+1/2x+2
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
y=-x^2+(1/2)x+2


y=-(x^2-(1/2)x-2)

y=-(x^2-(1/2)x+1/16-1/16-2)


y=-((x-1/4)^2-1/16-2)

y=-((x-1/4)^2-33/16)

y=-(x-1/4)^2+33/16

Vertex is (1/4, 33/16)