SOLUTION: The lenght of a rectangle is twice its width with an area of 2yds^2. I got that (L)(w)=area and L=2w (2x)(x)=2yds^2 This is where I get confused. Can someone help me out?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: The lenght of a rectangle is twice its width with an area of 2yds^2. I got that (L)(w)=area and L=2w (2x)(x)=2yds^2 This is where I get confused. Can someone help me out?      Log On


   

Question 279599: The lenght of a rectangle is twice its width with an area of 2yds^2.
I got that (L)(w)=area
and L=2w
(2x)(x)=2yds^2
This is where I get confused. Can someone help me out?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is twice its width with an area of 2yds^2.
I got that (L)(w)=area
and L=2w
(2x)(x)=2yds^2
This is where I get confused. Can someone help me out?
------------------
(2x)(x)=2yds^2
2x^2 = 2
x^2 = 1
x = 1 yd
-----------------------
Width = x = 1 yd
Length = 2x = 2 yd
========================
Cheers,
Stan H.