SOLUTION: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function. f(x)=1/5(x+2)^2+8

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function. f(x)=1/5(x+2)^2+8      Log On


   

Question 266719: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function.
f(x)=1/5(x+2)^2+8
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function.
f(x)=(1/5)(x+2)^2+8
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Vertex: (-2,8)
Axis of symmetry: x = -2
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Minimum value of f(x): f(x) = 8
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graph%28400%2C300%2C-10%2C10%2C-10%2C30%2C%281%2F5%29%28x%2B2%29%5E2%2B8%29
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Cheers,
Stan H.