Question 252441: one of the roots of the equation 5x^2 + kx = 4 is x = -2 the other root is
x = ...what ?
a -5/2 b -2/5 c 2/5 d 2 e 5/2 Found 2 solutions by richwmiller, stanbon:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! plug -2 in for x and solve for k
then solve the equation
5(-2)^2+k(-2)=4
5*4-2k=4
subtract 4 from each side
4*4-2k=0
add 2k to each side
16=2k
8=k
5x^2+8x=4
5x^2+8x-4=0
You can put this solution on YOUR website! one of the roots of the equation 5x^2 + kx = 4 is x = -2 the other root is
x = ...what ?
--------------------------
f(-2) = 0
5(-2)^2+k(-2)= 4
20-2k=4
2k = 16
k = 8
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5x^2+8x-4 = 0
5x^2+10x-2x-4 = 0
5x(x+2)-2(x+2) = 0
(x-2)(5x-2) = 0
x = 2 or x = 2/5
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Ans: x = 2/5
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Cheers,
Stan H.