SOLUTION: "Word Problems Involving Products and Factoring"
Find two consecutive positive numbers such that the product of the sum and difference of the numbers plus 8 is the sum of their sq
Question 252414: "Word Problems Involving Products and Factoring"
Find two consecutive positive numbers such that the product of the sum and difference of the numbers plus 8 is the sum of their squares. can you solve this pls=( tyty so much Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Find two consecutive positive numbers
x, (x+1)
:
such that the product of the sum and difference of the numbers plus 8 is the sum of their squares.
(x + (x+1))*((x+1)-x) + 8 = x^2 + (x+1)^2
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((2x+1) * 1) + 8 = x^2 + (x^2 + 2x + 1)
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2x + 9 = 2x^2 + 2x + 1
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9 - 1 = 2x^2 + 2x - 2x
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8 = 2x^2
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4 = x^2
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x = 2 and 3 are the numbers
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Check in statement
"the product of the sum and difference of the numbers plus 8 is the sum of their squares.
(2+3) * (3-2) + 8 = 2^2 + 3^2
5 + 8 = 4 + 9
