SOLUTION: a^2-11a+28=0

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Question 249999: a^2-11a+28=0
Answer by mathitutor(25) About Me  (Show Source):
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a^2-11a+28= a^2-7a - 4a+28= a(a-7) -4(a-7)=(a-4)(a-7)=0 Hence a = 4 and 7