SOLUTION: x^2-8x+15=0 how do you solve this problem, and how do you use the discriminant?

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Question 249938: x^2-8x+15=0
how do you solve this problem, and how do you use the discriminant?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
x^2-8x+15=0
(x-5)(x-3)=0
x-5=0
x=5 ans.
x-3=0
x=3 ans.
The discriminate is b^2-4ac.
-8^2-4*1*15=-64-60=4
Because the answer is a perect square then the answers are 2 real rational numbers.