Question 242047: If the base of a triangle is 8x+16 yards, and its height is 1 over x+2 yards (written as a fraction), then what is the area of the triangle?
Thank you!
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! b = 8x+16
h = 1/(x+2)
a = (1/2)*b*h
your formula is:
a = (1/2)*b*h = (1/2)*(8x+16)*(1/(x+2)
(1/2)*(8x+16) = (4x+8)
(4x+8) = 4*(x+2)
your equation becomes:
(4*(x+2))*(1/(x+2)
this equals 4 because (x+2)/(x+2) = 1
your area is equal to 4 regardless of the value of x.
when x = 1, your formula of
a = (1/2)*(8x+16)*(1/(x+2) becomes:
a = (1/2)*24*(1/3) = 12/3 = 4
when x = 4, your formula of
a = (1/2)*(8x+16)*(1/(x+2) becomes:
a = (1/2)*(48)*(1/6) = 24/6 = 4
etc.
your answer is the area = 4 yards
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