Question 241790: y=-16x^2+88x+24 how do you solve that with the quadratic equation?
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! -16x^2+88x+24 = 0
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-8(2x^2 - 11x - 3) = 0
a = 2 ; b = -11 ; c = -3
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Quadratic Formula:
x = [11 +- sqrt(121 - 4*2*-3)]/4
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x = [11 +- sqrt(145)]/4
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x = (11/4) + (1/4)sqrt(145) or x = (11/4) - (1/4)sqrt(145)
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Cheers,
Stan H.
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