SOLUTION: Solve the following equation using quadratic formula: x^2+12+35=0 The solution set is { , } x=(-12±√(〖12〗^2+35))/2 (x+5)(x+7)= 12/2= {5,7} tha

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Solve the following equation using quadratic formula: x^2+12+35=0 The solution set is { , } x=(-12±√(〖12〗^2+35))/2 (x+5)(x+7)= 12/2= {5,7} tha      Log On


   

Question 241028: Solve the following equation using quadratic formula:
x^2+12+35=0
The solution set is { , }

x=(-12±√(〖12〗^2+35))/2

(x+5)(x+7)= 12/2= {5,7}
thanks for you help
Vicki
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
The quadratic formula is x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

In this case, x^2 +12x+35=0, a=1, b=12, and c=35.

x=%28-12%2B-sqrt%28144-4%2A1%2A35%29%29%2F%282%2A1%29
x=%28-12%2B-sqrt%28144-140%29%29%2F2
x=%28-12%2B-sqrt%284%29%29%2F2
x=%28-12%2B-2%29%2F2
x=%28-12%2B2%29%2F2 or x=%28-12-2%29%2F2
x=-10%2F2=-5 or x=-14%2F2=-7

This problem can be checked by solving by FACTORING:
x^2 +12x+35=0
(x+5)(x+7)=0
x=-5 or x=-7

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Seminole State College of Florida
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