Question 232290: Story problem:
A tennis ball is hit upward with a velocity of 48 feet per second. Ignoring the height of the tennis player, how long does it take for the ball to fall to the ground?
Formula:
h(t)= v0t-16t^2
h(t) is height of an object (feet)
v0 is object's initial velocity (feet per second)
t is time (seconds)
so far i have 3 seconds but that is just one of the roots of the quadratic, not time.
??????
Thanks.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A tennis ball is hit upward with a velocity of 48 feet per second. Ignoring the height of the tennis player, how long does it take for the ball to fall to the ground?
Formula:
h(t)= v0t-16t^2
h(t) is height of an object (feet)
v0 is object's initial velocity (feet per second)
t is time (seconds)
so far i have 3 seconds but that is just one of the roots of the quadratic, not time.
---------------------
When it hits the ground its height is zero.
Solve for t: 48t - 16t^2 = 0
16t(3-t) = 0
t = 0 seconds or t=3 seconds
---
Explanation:
At t=0 seconds the ball is on the ground and about to be thrown upward.
At t=3 seconds the ball is again on the ground having fallen from its
highest point.
=======================================
Cheers,
Stan H.
|
|
|
