SOLUTION: Use the quadratic formula to determine the exacty solutions of each quadratic equation. Then approximate each solution to the nearest hundredth. y^2 - 5 = 0 5w^2 = 2w + 1

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Use the quadratic formula to determine the exacty solutions of each quadratic equation. Then approximate each solution to the nearest hundredth. y^2 - 5 = 0 5w^2 = 2w + 1      Log On


   

Question 232014: Use the quadratic formula to determine the exacty solutions of each quadratic equation. Then approximate each solution to the nearest hundredth.
y^2 - 5 = 0

5w^2 = 2w + 1
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Use the quadratic formula to determine the exacty solutions of each quadratic equation. Then approximate each solution to the nearest hundredth.
y^2 - 5 = 0
y^2 = 5
y = +/-sqrt%285%29
That is:
y ~ +/- 2.24
:
5w^2 = 2w + 1
5w^2 - 2w - 1 = 0
The quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
In this problem x - w; a=5; b=-2; c=-1
w+=+%28-%28-2%29+%2B-+sqrt%28-2%5E2+-+4%2A5%2A-1+%29%29%2F%282%2A5%29+
:
w+=+%282+%2B-+sqrt%284+-+%28-20%29+%29%29%2F10+
:
w+=+%282+%2B-+sqrt%284+%2B+20+%29%29%2F10+
;
w+=+%282+%2B-+sqrt%2824+%29%29%2F10+
Two solutions
w+=+%282+%2B4.89898%29%2F10
w = 6.89898%2F10
w ~ .69
And
w+=+%282+-+4.89898%29%2F10
w = -2.89898%2F10
w ~ -.29