Question 217609: a rectangular room has a permeter of 48 ft. the width is two-thirds of the length. what are the dimensions of the room?
Found 2 solutions by rfer, MathTherapy:
Answer by rfer(16322)   (Show Source):
Answer by MathTherapy(10549)  (Show Source):
You can put this solution on YOUR website! a rectangular room has a permeter of 48 ft. the width is two-thirds of the length. what are the dimensions of the room?
Let the length of the room be L. Then the width is  of L, or 
Since perimeter = 48, and perimeter = 2L + 2W, then we'll have:  , or, 
6L + 4L = 144 ----- Multiply by LCD, 3
10L = 144
 ft.
Therefore, length of the room, or L =  ft, and its width = of  ft, or  ft.
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Check
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2L + 2W = 48
2(14.4) + 2(9.6) = 48
28.8 + 19.2 = 48 (TRUE)
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