SOLUTION: a farmer wants to set up a pigpen using 40 feet of fence to enclose a rectangular area of 51 square feet. what are the dimensions of the pigpen?
Question 211995: a farmer wants to set up a pigpen using 40 feet of fence to enclose a rectangular area of 51 square feet. what are the dimensions of the pigpen? Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! A farmer wants to set up a pigpen using 40 feet of fence to enclose a rectangular area of 51 square feet. what are the dimensions of the pigpen?
1. Perimeter of a rectangle is 2x+2y=40 where x=one side of rectangle and y=the adjacent side of x. We can simplify this as x+y=20 where we divided 2 on both sides of the equation. That is,
2. Area=xy=51 where area of rectangle is height times width.
3. Substitute y in Step 1 into Step 2.
Multiplying the terms will yield:
4. Put everything on the left side to the right. That is, add -20x+x^2 from both sides of the equation to make the left side equal to zero.
Simplifying will yield
Finally, the above equation is equivalent to
4. Now this is just a Quadratic Equation so we can use the formula
where a=1, b=-20 and c=51
5. Use the following steps to solve the quadratic equation.