SOLUTION: How would I turn this quadratic {{{x^2-2x-8}}} into turning point form?

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Question 208165: How would I turn this quadratic x%5E2-2x-8 into turning point form?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-2x-8
.
Complete the square and convert to "vertex form" or "turning point":
y= a(x-h)^2+k
where (h,k) is the turning point (vertex)
.
x%5E2-2x-8
%28x%5E2-2x%2B1%29-8-1
%28x-1%29%28x-1%29-9
%28x-1%29%5E2-9
.
Therefore, the vertex is at (1,-9)