SOLUTION: solve by using quadratic formula (((6x2+3x-18=0))) my answer is x=-2 3/2 -b+- sq root of b^2-4ac/2a a=6 b=3 c=18 so -3+-sqrt[9-4(6)(-18)]/12 -3+-sqrt(441)/12 (-3+-21)/12 an

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: solve by using quadratic formula (((6x2+3x-18=0))) my answer is x=-2 3/2 -b+- sq root of b^2-4ac/2a a=6 b=3 c=18 so -3+-sqrt[9-4(6)(-18)]/12 -3+-sqrt(441)/12 (-3+-21)/12 an      Log On


   

Question 204724: solve by using quadratic formula (((6x2+3x-18=0)))
my answer is x=-2 3/2
-b+- sq root of b^2-4ac/2a
a=6
b=3
c=18
so -3+-sqrt[9-4(6)(-18)]/12
-3+-sqrt(441)/12
(-3+-21)/12 and x=(-3-21)/12
x=-3+21/12 and x=-3-21/12
x=18/12=3/2 and x=-2
this is how I came up with this answer is this right?
Answer by lazi(15) About Me  (Show Source):
You can put this solution on YOUR website!
it's right. But next time to check if your answers are right just plug the x's into the original formula (6x^2+3x-18=0) and see whether it's actually equals.