SOLUTION: Give exact and approximate solutions to three decimal places (x+9)^2=16

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Question 185634: Give exact and approximate solutions to three decimal places
(x+9)^2=16
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%28x%2B9%29%5E2=16 Start with the given equation.


x%2B9=0%2B-sqrt%2816%29 Take the square root of both sides.


x%2B9=sqrt%2816%29 or x%2B9=-sqrt%2816%29 Break up the "plus/minus" to form two equations.


x%2B9=4 or x%2B9=-4 Take the square root of 16 to get 4.


x=-9%2B4 or x=-9-4 Subtract 9 from both sides.


x=-5 or x=-13 Combine like terms.


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Answer:


So the solutions are x=-5 or x=-13.