SOLUTION: Write the equation of a quadratic that has zeros of 5 and 1 with F(0)=1. I understand you need to multiply (x-5)(x-1) to get the polynomial, but f(0) wouldnt equal 1. PLEASE HELP M
Question 166604: Write the equation of a quadratic that has zeros of 5 and 1 with F(0)=1. I understand you need to multiply (x-5)(x-1) to get the polynomial, but f(0) wouldnt equal 1. PLEASE HELP ME OUT!!! Found 2 solutions by nerdybill, stanbon:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! As you say:
(x-5)(x-1)
x^2 - x - 5x + 5
x^2 - 6x + 5
.
So,
F(x) = x^2 - 6x + 5
.
F(1) = 1^2 - 6(1) + 5
F(1) = 1 - 6 + 5
F(1) = 0
.
You can put this solution on YOUR website! Write the equation of a quadratic that has zeros of 5 and 1 with F(0)=1. I understand you need to multiply (x-5)(x-1) to get the polynomial, but f(0) wouldnt equal 1.
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Right. That is why you need a variable factor,like "k" below.
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f(x) = k(x-5)(x-1)
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Now you get f(0) = k(-5)(-1) = 1
5k = 1
k = 1/5
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EQUATION:
y = (1/5)(x-5)(x-1)
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Cheers,
Stan H.
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