SOLUTION: 3x^2+19x-14=0 then I have to write it in the quadratic formula. -19+-sqrt(-19^2-4*3*-14/2*19; x=19+sqrt361+168/38; 19+-sqrt529/38; x=19+-23/38; x=42/38=6/2; x=6/2=-4 I got the -4 s

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: 3x^2+19x-14=0 then I have to write it in the quadratic formula. -19+-sqrt(-19^2-4*3*-14/2*19; x=19+sqrt361+168/38; 19+-sqrt529/38; x=19+-23/38; x=42/38=6/2; x=6/2=-4 I got the -4 s      Log On


   

Question 150123This question is from textbook
: 3x^2+19x-14=0 then I have to write it in the quadratic formula. -19+-sqrt(-19^2-4*3*-14/2*19; x=19+sqrt361+168/38; 19+-sqrt529/38; x=19+-23/38; x=42/38=6/2; x=6/2=-4 I got the -4 sub 19 from 23 to get the -4. Can you please tell me if this is right because there is alot of steps to this thank you. This question is from textbook

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Yes, there are a lot of steps.
You started out with a mistake in the denominator, 19 instead of 3.
x=%28-19%2B-sqrt%28%28-19%29%5E2-4%2A3%2A%28-14%29%29%29%2F%282%2Ahighlight%283%29%29
and made a minor mistake along the way.
x=%28highlight%28-19%29%2B-sqrt%28361%2B168%29%29%2F6
You lost the negative sign in front of 19.
x=%28-19%2B-sqrt%28529%29%29%2F6
x=%28-19+%2B-+23%29%2F6
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First solution
x=%28-19%2B23%29%2F6
x=4%2F6
x=2%2F3 Answer in lowest terms
Second solution
x=%28-19-23%29%2F6
x=-42%2F6
x=-7 Answer in lowest terms
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I'm not sure about x=6/2=-4??
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Remember you can always check your answer by plugging it back into the equation.
3x%5E2%2B19x-14=0
3%28-7%29%5E2%2B19%28-7%29-14=0
147-133-14=0
0=0
Good answer.