SOLUTION: A company uses the formula C(x)= 0.02x^2-3.4x + 150 to model the unit cost in dollars for producing x stabilizer bars. For what number of bars is the unit cost at its minimum? What

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: A company uses the formula C(x)= 0.02x^2-3.4x + 150 to model the unit cost in dollars for producing x stabilizer bars. For what number of bars is the unit cost at its minimum? What      Log On


   



Question 149908: A company uses the formula C(x)= 0.02x^2-3.4x + 150 to model the unit cost in dollars for producing x stabilizer bars. For what number of bars is the unit cost at its minimum? What is the unit cost at that level of production?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A company uses the formula C(x)= 0.02x^2-3.4x + 150 to model the unit cost in dollars for producing x stabilizer bars. For what number of bars is the unit cost at its minimum? What is the unit cost at that level of production?
------------------
C(x)= 0.02x^2-3.4x + 150
To find the minimum, set the 1st derivative to 0
0.04x - 3.4 = 0
Multiply by 100
4x = 340
x = 85
-------
Sub 85 for x in the equation
C(x)= 0.02x^2-3.4x + 150
C(85) = 0.02*85*85 - 3.4*85 + 150
= $583.50
That's the cost of 85 bars.
For one, $583.50/85 = $6.865