SOLUTION: What do I solve this by factoring? 49x^2 - 14x - 3 Thanks!

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: What do I solve this by factoring? 49x^2 - 14x - 3 Thanks!      Log On


   



Question 139520: What do I solve this by factoring?
49x^2 - 14x - 3
Thanks!

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at 49x%5E2-14x-3 we can see that the first term is 49x%5E2 and the last term is -3 where the coefficients are 49 and -3 respectively.

Now multiply the first coefficient 49 and the last coefficient -3 to get -147. Now what two numbers multiply to -147 and add to the middle coefficient -14? Let's list all of the factors of -147:



Factors of -147:
1,3,7,21,49,147

-1,-3,-7,-21,-49,-147 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -147
(1)*(-147)
(3)*(-49)
(7)*(-21)
(-1)*(147)
(-3)*(49)
(-7)*(21)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to -14? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -14

First NumberSecond NumberSum
1-1471+(-147)=-146
3-493+(-49)=-46
7-217+(-21)=-14
-1147-1+147=146
-349-3+49=46
-721-7+21=14



From this list we can see that 7 and -21 add up to -14 and multiply to -147


Now looking at the expression 49x%5E2-14x-3, replace -14x with 7x%2B-21x (notice 7x%2B-21x adds up to -14x. So it is equivalent to -14x)

49x%5E2%2Bhighlight%287x%2B-21x%29%2B-3


Now let's factor 49x%5E2%2B7x-21x-3 by grouping:


%2849x%5E2%2B7x%29%2B%28-21x-3%29 Group like terms


7x%287x%2B1%29-3%287x%2B1%29 Factor out the GCF of 7x out of the first group. Factor out the GCF of -3 out of the second group


%287x-3%29%287x%2B1%29 Since we have a common term of 7x%2B1, we can combine like terms

So 49x%5E2%2B7x-21x-3 factors to %287x-3%29%287x%2B1%29


So this also means that 49x%5E2-14x-3 factors to %287x-3%29%287x%2B1%29 (since 49x%5E2-14x-3 is equivalent to 49x%5E2%2B7x-21x-3)





%287x-3%29%287x%2B1%29=0 Set the factorization equal to zero



Now set each factor equal to zero:
7x-3=0 or 7x%2B1=0

x=3%2F7 or x=-1%2F7 Now solve for x in each case



-------------------------
Answer:

So our solutions are

x=3%2F7 or x=-1%2F7