SOLUTION: Help with translating this into a quadratic equation to solve. Thanks! A photo is 3 inches longer that it is wide. A 2 inch border is placed around the photo making the total ar

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Help with translating this into a quadratic equation to solve. Thanks! A photo is 3 inches longer that it is wide. A 2 inch border is placed around the photo making the total ar      Log On


   

Question 139338: Help with translating this into a quadratic equation to solve. Thanks!
A photo is 3 inches longer that it is wide. A 2 inch border is placed around the photo making the total area of the photo and border 108in^2. What are the dimensions of the photo?
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Help with translating this into a quadratic equation to solve. Thanks!
A photo is 3 inches longer that it is wide. A 2 inch border is placed around the photo making the total area of the photo and border 108in^2. What are the dimensions of the photo?
:
Let x = width of the photo
then
(x+3 = the length of the photo
:
The dimensions of the total area (photo and border):
(x+4) = width
and
(x+3)+4 =
which is:
(x+7) = length
:
Total area equation:
(x+4)(x+7) = 108
FOIL
x^2 + 11x + 28 = 108
:
x^2 + 11x + 28 - 108 = 0
The quadratic equation
x^2 + 11x - 80 = 0
:
:
Solve this for x to get the width of the photo