Question 139130This question is from textbook martin gaye :beginning & intermidiate algebra, 3e
: Do these equations have a maximum or a minimum? What is the maximum or minimum point? g(x) = -x^2 + 4x + 5 and f(x) = 2(x+3)^2 - 4....i can't really show what i have tried because i don't know how to figure this out, sorry!! please help?!
This question is from textbook martin gaye :beginning & intermidiate algebra, 3e
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Do these equations have a maximum or a minimum? What is the maximum or minimum point?
g(x) = -x^2 + 4x + 5
Vertex at x = -b/2a = -4/(2*-1) = 4
g(4) = 5
Vertex: (4.5)
This is a maximum because the coefficient of x^2 is negative.
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and f(x) = 2(x+3)^2 - 4....
f(x)+4 = 2(x+3)^2
This is the form y-k = a(x-h)^2
h=-3 ; k=-4
Vertex: (-3,-4)
This is a minimum point because the coefficient of x^2 is positive.
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Cheers,
Stan H.
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