SOLUTION: It is estimated that each guest at a party will eat 3/7 pounds of chocolates. How many guests can be served with 9 pounds of chocolate?

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Question 1202541: It is estimated that each guest at a party will eat 3/7 pounds of chocolates. How many guests can be served with 9 pounds of chocolate?
Found 3 solutions by josgarithmetic, ikleyn, math_tutor2020:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Uncomplicated as described. What exactly do you not understand?




21 guests

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.

To answer this question, divide 9 pounds by 3%2F7 pounds, which value is "the consumption rate per person" in this problem.


The calculation is presented in the next line, which follows

    "How many guests" = 9%2F%28%283%2F7%29%29 = %289%2A7%29%2F3 = 3*7 = 21.


ANSWER.  21 guests.

Solved.



Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

n = number of guests

1 guest eats 3/7 of a pound of chocolate.
n guests eat (3/7)n pounds of chocolate.

(3/7)n = 9
3n = 7*9
3n = 63
n = 63/3
n = 21

Answer: 21 guests can be served.

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Another approach:

Draw 9 rectangles to represent the 9 pounds of chocolate.
Split each rectangle into 7 equal smaller pieces. There will be 7*9 = 63 smaller pieces.
Each small piece represents 1/7 of a pound of chocolate.

Each guest eats 3/7 of a pound. It means each person eats 3 smaller blocks, so 63/3 = 21 guests can be served.