SOLUTION: Determine the value of 'k' if the product of the roots of 3kx^2+2(x-1)+k=0 is 1.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Determine the value of 'k' if the product of the roots of 3kx^2+2(x-1)+k=0 is 1.      Log On


   



Question 119097: Determine the value of 'k' if the product of the roots of 3kx^2+2(x-1)+k=0 is 1.
Found 2 solutions by josmiceli, solver91311:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
3kx%5E2+%2B+2%28x-1%29+%2B+k+=+0
3kx%5E2+%2B+2x+-+2+%2B+k+=+0
The equation can also be expressed as
%28x+-+r%5B1%5D%29%28x+-+r%5B2%5D%29+=+0
x%5E2+-+%28r%5B1%5D+%2B+r%5B2%5D%29x+%2B+r%5B1%5Dr%5B2%5D+=+0
If i divide both sides of the given equation by 3k, I get
x%5E2+%2B+2x+%2F+3k+%2B+%28k+-+2%29+%2F+3k+=+0
matching up the terms, I get
%28k+-+2%29%2F3k+=+r%5B1%5Dr%5B2%5D
The problem says the product of the roots = 1, so
%28k+-+2%29%2F3k+=+1
solve for k
k+-+2+=+3k
2k+=+-2
k+=+-1

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
3kx%5E2%2B2%28x-1%29%2Bk=0

Step 1: Put the equation into standard form, i.e. ax%5E2%2Bbx%2Bc=0

3kx%5E2%2B2x-2%2Bk=0 or more neatly: 3kx%5E2%2B2x%2Bk-2=0

Step 2: Apply the quadratic formula with a=3k, b=2, and c=k-2

x+=+%28-2+%2B-+sqrt%28+4-4%2A%283k%29%2A%28k-2%29+%29%29%2F%282%2A3k%29+

Step 3: Simplify

x+=+%28-2+%2B-+sqrt%28+4-12k%5E2%2B24k%29+%29%2F%286k%29+

Step 4: We are looking for k such that x%5B1%5Dx%5B2%5D=1, so:



Step 5: This looks like a hideous mess to multiply, but remember that %28a%2Bb%29%28a-b%29=a%5E2-b%5E2, so:

%284-%284-12k%5E2%2B24k%29%29%2F36k%5E2=1

Step 6: Simplify and solve

%284-%284-12k%5E2%2B24k%29%29%2F36k%5E2=1
%2812k%5E2-24k%29%2F36k%5E2=1
12k%5E2-24k=36k%5E2
-24k%5E2-24k=0
k%5E2%2Bk=0
k%28k%2B1%29=0

So k+=+0 or k=-1

Step 7: k=0 can be excluded because that would make the lead coefficient on the original quadradic go to zero. Therefore, k=-1

Step 8: Check the answer. Using k=-1, the original quadratic becomes

-3x%5E2%2B2x-3=0



The product of these two roots should be 1: Does %28%28-1%2Bsqrt%282%292i%29%2F3%29%28%28-1-sqrt%282%292i%29%2F3%29=1?

Again, we can simplify something that looks rather messy with the difference of two squares factorization, %28a%2Bb%29%28a-b%29=a%5E2-b%5E2,

: Answer checks.