SOLUTION: (n-1)(n)(n+1)=210
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Question 119071
:
(n-1)(n)(n+1)=210
Found 2 solutions by
checkley71, stanbon
:
Answer by
checkley71(8403)
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(N-1)N(N+1)=210
N-1,N,N+1 ARE 3 CONSECUTIVE NUMBERS WHOSE AVERAGE IS N
THEREFORE 210/3=70=N
N-1=69, N=70 & N=1-71.
PROOF
69+70+71=210
210=210
Answer by
stanbon(75887)
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(n-1)(n)(n+1)=210
n(n^2-1)-210 = 0
n^3-n-210 = 0
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I graphed it to find n = 6
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Cheers,
Stan H.