SOLUTION: An Acapulco cliff diver dives into the sea from a height of 35 m. His height, h, in meters t
seconds after leaving the cliff is given by the equation h=-4.9t^2 + t + 35
a) Find
Question 1181717: An Acapulco cliff diver dives into the sea from a height of 35 m. His height, h, in meters t
seconds after leaving the cliff is given by the equation h=-4.9t^2 + t + 35
a) Find the diver’s initial height.
b) Find the diver’s height after 1.5 seconds.
c) How long is it until the diver reaches the water? Round answer to the nearest hundredth. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! the initial height is the constant 35 m in the equation.
after 1.5 seconds, h(1.5)=4.9*2.25+1.5+35=25.475 m
when hits water h(t)=0
so -4.9t^2+t+35=0 or 4.9t^2-t-35=0
t=(1/9.8)(1+/- sqrt(1+686)); sqrt(687)=26.21
t=27.21/9.8 for only positive root=2.78 seconds
