SOLUTION: Solve for the solution over the domain: -180 < or equal to x < or equal to 360 degrees. Equation is : 2= sq.root2 cos((1/2)(x-30degrees)) +1

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Solve for the solution over the domain: -180 < or equal to x < or equal to 360 degrees. Equation is : 2= sq.root2 cos((1/2)(x-30degrees)) +1       Log On


   



Question 1173666: Solve for the solution over the domain: -180 < or equal to x < or equal to 360 degrees.
Equation is : 2= sq.root2 cos((1/2)(x-30degrees)) +1

Found 3 solutions by Edwin McCravy, mccravyedwin, AnlytcPhil:
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

2%22%22=%22%22sqrt%282%29cos%5E%22%22%28expr%281%2F2%29%28x-30%5Eo%29%29%2B1 

Subtract 1 from both sides:

1%22%22=%22%22sqrt%282%29cos%5E%22%22%28expr%281%2F2%29%28x-30%5Eo%29%29

Divide both sides by √2

1%2Fsqrt%282%29%22%22=%22%22cos%5E%22%22%28expr%281%2F2%29%28x-30%5Eo%29%29

Use the half-angle formula:  

1%2Fsqrt%282%29%22%22=%22%22 

Square both sides:

1%2F2%22%22=%22%22expr%281%2F2%29%281%5E%22%22%5E%22%22%2Bcos%5E%22%22%28x-30%5Eo%29%29 

Multiply both sides by 2:

1%22%22=%22%221%2Bcos%5E%22%22%28x-30%5Eo%29

Subtract 1 from both sides of the equation:

0%22%22=%22%22cos%5E%22%22%28x-30%5Eo%29

%282n%2B1%2990%5Eo%22%22=%22%22x-30%5Eo

n%2A180%5Eo%2B90%5Eo%22%22=%22%22x-30%5Eo

Add 30o to both sides

n%2A180%5Eo%2B120%5Eo%22%22=%22%22x

Since we are given:

-180%5Eo%3C=+x%3C=+360%5Eo

-180%5Eo%3C=n%2A180%5Eo%2B120%5Eo%3C=+360%5Eo

We subtract 120o from all three sides

-300%5Eo%3C=n%2A180%5Eo%3C=240%5Eo

Divide all three sides by 180°

-300%5Eo%2F180%5Eo%3C=n%2A180%5Eo%2F180%5Eo%3C=240%5Eo%2F180%5Eo

-5%2F3%3C=n%3C=4%2F3

-1%262%2F3%3C=n%3C=1%261%2F3

Since n must be an integer,

-1%3C=n%3C=1

So n = -1, 0, 1

Since

n%2A180%5Eo%2B120%5Eo%22%22=%22%22x,

For n = -1

-1%2A180%5Eo%2B120%5Eo%22%22=%22%22x
-60%5Eo%22%22=%22%22x

For n = 0

0%2A180%5Eo%2B120%5Eo%22%22=%22%22x
120%5Eo%22%22=%22%22x

For n = 1

1%2A180%5Eo%2B120%5Eo%22%22=%22%22x
300%5Eo%22%22=%22%22x

However, we squared both sides and that means that there may be
one or more extraneous solutions.

If we check each one using a calculator, we find that 300° is
not a solution and that there are only two solutions,

-60° and 120° 

Edwin



Answer by mccravyedwin(405) About Me  (Show Source):
You can put this solution on YOUR website!

I realized there was a simpler solution without extraneous solutions:

2%22%22=%22%22sqrt%282%29cos%5E%22%22%28expr%281%2F2%29%28x-30%5Eo%29%29%2B1 

Subtract 1 from both sides:

1%22%22=%22%22sqrt%282%29cos%5E%22%22%28expr%281%2F2%29%28x-30%5Eo%29%29

Divide both sides by √2

1%2Fsqrt%282%29%22%22=%22%22cos%5E%22%22%28expr%281%2F2%29%28x-30%5Eo%29%29

sqrt%282%29%2F2%22%22=%22%22cos%5E%22%22%28expr%281%2F2%29%28x-30%5Eo%29%29

expr%281%2F2%29%28x-30%5Eo%29%22%22=%22%22%22%22+%2B-+45%5Eo+%2Bn%2A360%5Eo

Multiply both sides by 2

x-30%5Eo%22%22=%22%22%22%22+%2B-+90%5Eo+%2Bn%2A720%5Eo

Add 30° to both sides

x%22%22=%22%2230%5Eo+%2B-+90%5Eo+%2Bn%2A720%5Eo

Since we are given:

-180%5Eo%3C=+x%3C=+360%5Eo

-180%5Eo%3C=30%5Eo+%2B-+90%5Eo+%2Bn%2A720%5Eo+%3C=360%5Eo

We subtract 30° from all three sides

-210%5Eo%3C=%22%22+%2B-+90%5Eo+%2Bn%2A720%5Eo+%3C=330%5Eo

We subtract or add 90° from/to all three sides:

-210%5Eo+%2B-+90%5Eo%3C=n%2A720%5Eo+%3C=330%5Eo+%2B-+90%5Eo

Divide all three sides by 720°

-210%5Eo%2F720%5Eo+%2B-+90%5Eo%2F720%5Eo%3C=n+%3C=330%5Eo%2F720%5Eo+%2B-+90%5Eo%2F720%5Eo

-7%2F24+%2B-+1%2F8%3C=n%3C=11%2F24+%2B-+1%2F3

Using the +

-7%2F24+%2B+1%2F8%3C=n%3C=11%2F24+%2B+1%2F3

-1%2F6+%3C=+n+%3C=+19%2F24

Since n is an integer, n=0

x%22%22=%22%2230%5Eo+%2B+90%5Eo+%2B0%2A720%5Eo

x%22%22=%22%22120%5Eo

Using the -

-7%2F24+-+1%2F8%3C=n%3C=11%2F24+-+1%2F3

-5%2F12+%3C=+n+%3C=+1%2F8

Since n is an integer, n=0

x%22%22=%22%2230%5Eo+-+90%5Eo+%2B0%2A720%5Eo

x%22%22=%22%22-60%5Eo

There are two solutions:

-60° and 120° 

Edwin

Answer by AnlytcPhil(1806) About Me  (Show Source):