SOLUTION: Please help Solve the quadratic equation by completing the square. {{{ x^2-4x-6=0 }}}

You start with

    x^2 - 4x - 6 = 0


The term  "-4x "  says you that the expected square term should be {x-2)^2 = x^2 - 4x + 4


So we add 10 to both sides

    x^2 - 4x + 10 - 6 = 10,   or

    x^2 - 4x + 4 = 10.


In the left side you just have the desired square:

    {x - 2)^2 = 10.


Now take the square root from both sides

    x - 2 = +/- 


Your last step is to move -2 from the left side to the right, changing the sign

    x = 2 +/- .


The problem is just solved.


ANSWER.  The given equation has two roots  x = 2 +   and  x = 2 - .

Hi  
Solve the quadratic equation by completing the square.
  Or 
(x-2)^2 - 4 - 6 = 0
(x-2)^2 = 10   Taking the Square Root of both sides
x - 2 = ± √10  
x = 2 ± √10 
Wish You the Best in your Studies.

 ------------- Adding 6 to both sides to move constant to right of equals sign

 ------ Taking  of b, squaring it, and then ADDING the result to both sides of equation

 ------ Substituting - 4 for b



 ------- Taking square root of both sides