SOLUTION: One leg of a right triangle is 44 inches more than twicetwice the length of the other leg. The hypotenuse is 5 inches more than the shorter leg. Find the lengths of all

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: One leg of a right triangle is 44 inches more than twicetwice the length of the other leg. The hypotenuse is 5 inches more than the shorter leg. Find the lengths of all       Log On


   

Question 1156595: One leg of a right triangle is
44
inches more than
twicetwice
the length of the other leg. The hypotenuse is
5
inches more than the shorter leg. Find the lengths of all the sides.
Found 3 solutions by MathLover1, Alan3354, josgarithmetic:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

are you sure that
one leg is 44 inches more than twice the length of the other leg and the hypotenuse is 5 inches more than the shorter leg?????/////

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
One leg of a right triangle is
44
inches more than
twicetwice
the length of the other leg. The hypotenuse is
5
inches more than the shorter leg. Find the lengths of all the sides.
=============================
Makes the hypotenuse shorter than at least 1 of the legs.
Not possible.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming the 4 was doubled in entering by mistake,
leg, 2x+4
short leg, x
hypotenuse, x+5

Pythagorean Theorem: %282x%2B4%29%5E2%2Bx%5E2=%28x%2B5%29%5E2
.
.
4x%5E2%2B6x-9=0

Using general solution formula and accepting only positive value,
x=%28-3%2B3sqrt%285%29%29%2F4, the short leg.
NOW recheck if this makes any sense. Look again at the original expressions from the problem description. Can you have 2x%2B4%3Cx%2B5 ? Does this match with the "solved" value for x?


-
x=0.927 to three sig figrs.