SOLUTION: I'm having confusion with this question You and a friend are hiking in the mountains. You want to climb a ledge that is 6.1 meters above you. The height of the grappling hook yo

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: I'm having confusion with this question You and a friend are hiking in the mountains. You want to climb a ledge that is 6.1 meters above you. The height of the grappling hook yo      Log On


   

Question 1141983: I'm having confusion with this question
You and a friend are hiking in the mountains. You want to climb a ledge that is 6.1 meters above you. The height of the grappling hook you throw is modeled by the equations h(t)=-4.903t^2+9.8t+1.5. What is the maximum height of the grappling hook? Can you throw it high enough to reach the ledge?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
The vertex of this negative quadratic has a t value of -b/2a
This is -9.8/-9.806 or 0.9994 seconds
put that back into the equation and h(0.9994)=-4.90+9.79+1.5=6.39 meters. That will be sufficient.