Question 1131446: 4/x+8 - 1/x-8=5x/x^2-64 I am needing help how to determine the values of the variable that makes a denominator zero,
Thanks so much!! Found 3 solutions by MathLover1, Boreal, MathTherapy:Answer by MathLover1(20849) (Show Source):
now we have same denominators and to determine the values of the variable that makes a denominator zero, set denominator to zero and solve for
solutions:
-> ->
these are the values of the variable that makes a denominator zero
You can put this solution on YOUR website! If it is 4/(x+8), when x=-8 the denominator is 0. Set the denominators to 0 and factor. The solutions will be the numbers not allowed in the domain.
(x-8) in a denominator means x=8 is not allowed.
x^2-64 factors into (x+8)(x-8), and +/-8 are not allowed.
You can put this solution on YOUR website! 4/x+8 - 1/x-8=5x/x^2-64 I am needing help how to determine the values of the variable that makes a denominator zero,
Thanks so much!!
------- Factoring denominator on right-side
As seen, the LCD is (x - 8)(x + 8), so you set each FACTOR equal to 0, and solve for x.
This should give you values: that will make the denominators 0, or each expression UNDEFINED.