SOLUTION: Find the x intercepts and the vertex of the parabola. (If an answer does not exist, enter DNE.) f(x) = x2 − 16x + 48 x= (smaller value) x= (larger value)

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: Find the x intercepts and the vertex of the parabola. (If an answer does not exist, enter DNE.) f(x) = x2 − 16x + 48 x= (smaller value) x= (larger value)      Log On


   

Question 1116524: Find the x intercepts and the vertex of the parabola. (If an answer does not exist, enter DNE.)
f(x) = x2 − 16x + 48
x= (smaller value)
x= (larger value)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the x intercepts and the vertex of the parabola. (If an answer does not exist, enter DNE.)
f(x) = x^2 − 16x + 48
To find the x-intercepts, solve the following::
x^2 - 16x + 48 = 0
(x-4)(x-12) = 0
x = 4 or x = 12
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The x-value of the vertex is midway between the x-intercepts::
That x-valsue is 4+ (12-4)/2 = 4+4 = 8
f(8) = 64 - 128 + 48
f(8) = -16
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Vertex is at (8,-16)
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Cheers,
Stan H.
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