SOLUTION: The sum of a number and its square is 4 more than twice the number. Find the number.

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Question 1085210: The sum of a number and its square is 4 more than twice the number. Find the number.
Found 3 solutions by stanbon, addingup, math_helper:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of a number and its square is 4 more than twice the number. Find the number.
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Equation:
x + x^2 = 2x+4
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x^2 -x - 4 = 0
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Quadratic formula::
x = [1 +-sqrt(1-4*-4)]/2
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x = [1 +- sqrt(17)]/2
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x = (1/2)+(1/2)sqrt(17) or x = (1/2)-(1/2)sqrt(17)
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Cheers,
Stan H.
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Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
x+x^2 = 2x+4
Subtract 2x+4 from both sides:
x^2-x-4 = 0
x^2-x = 4
x^2-x+1/4 = 17/4
(x-1/2)^2 = 17/4
x-1/2 = sqrt(17)/2 or x-1/2 = -sqrt(17)/2
x = 1/2+sqrt(17)/2 or x = 1/2-sqrt(17)/2

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
+x+%2B+x%5E2+=+4+%2B+2x+
+x%5E2+-+x+-+4+=+0+
+x+=+%28-%28-1%29+%2B-+sqrt%28++%28-1%29%5E2+-+4%2A%281%29%2A%28-4%29%29%29+%2F+2+
+x+=++1%2F2+%2B-+sqrt%2817%29+%2F+2+
Solutions: +x+=+%281%2Bsqrt%2817%29%29+%2F+2+ and +x+=+%281-sqrt%2817%29%29%2F2+