SOLUTION: how can you write 5-3x=2xsqaured in standard form?

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Question 1039419: how can you write 5-3x=2xsqaured in standard form?

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

5-3x%22%22=%22%222x%5E2

Standard form is Ax%5E2%2BBx%2BC%22%22=%22%220
where A is a positive number.

5-3x%22%22=%22%222x%5E2

Add -2x2 to both sides

5-3x-red%282x%5E2%29%22%22=%22%222x%5E2-red%282x%5E2%29

Rearrange terms in descending order on the left.
Right side becomes 0:

-2x%5E2-3x%2B5%22%22=%22%220

Since first term is negative, multiply every term by -1:

2x%5E2%2B3x-5%22%22=%22%220  <--- that's in standard form.  That's
                        all you were asked to do.  But
                        I'll go ahead and solve it.  

Factor the left side:

%282x%2B5%29%28x-1%29%22%22=%22%220

Use zero-factor property:

2x%2B5%22%22=%22%220;   x-1%22%22=%22%220
  2x%22%22=%22%22-5;    x%22%22=%22%221
   x%22%22=%22%22-5%2F2

Edwin